nemitom
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« on: March 09, 2020, 10:53:50 AM »
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Hello all, Looking for algo for EDC15 eeprom (VIN - CRC). Can anyone help?
e.g. VIN is TMBFP21U138669631 VIN to hex : 54 4D 42 46 50 32 31 55 31 33 38 36 36 39 36 33 31 CRC : "82"
how to calculate crc? Thanks all
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H2Deetoo
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« Reply #1 on: March 10, 2020, 10:17:59 AM »
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It is not encrypted. It is just a hexadecimal representation of ASCII characters..
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nemitom
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« Reply #2 on: March 10, 2020, 11:14:14 AM »
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I'm not saying it's encrypted. But how to calculate CRC?
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cherry
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« Reply #3 on: March 10, 2020, 11:36:35 AM »
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EDC15 eeprom crc? Sure? And even if there is a checksum, i would not expect it to vin range only, but for some block.
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nemitom
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« Reply #4 on: March 10, 2020, 02:39:15 PM »
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really.... crc only VIN and Immo ID.... if not correct "crc", ecu delete vin nr. and write all "x".....
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H2Deetoo
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« Reply #5 on: March 11, 2020, 01:58:49 AM »
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Most likely the checksum is just an addition, subtraction, maybe result inversed or a XOR. Finding the range is important.
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cherry
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« Reply #6 on: March 11, 2020, 07:10:24 AM »
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1 min google is enough to find solution for your problem. There are enough free tools for this. If you cannot find it just upload eeprom and new vin.
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nemitom
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« Reply #7 on: March 11, 2020, 12:31:54 PM »
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to cherry: I don't want to edit the file .... I want to know how ... finding algo
to H2Deetoo: I am aware of it, I was hoping that someone knows the way ... I have been solving it for a while and I have no solution ....
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cherry
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« Reply #8 on: March 11, 2020, 01:18:29 PM »
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Then download some simple EDC15 tool and figure out how it works with several tests. Maybe take a look to ME7 eeprom checksum also to get a starting point of understanding, there is description in board somewhere.
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nemitom
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« Reply #9 on: March 12, 2020, 05:20:15 AM »
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Solved thanks!!
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nyet
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« Reply #10 on: March 14, 2020, 06:01:04 PM »
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Solved thanks!!
And the solution was?
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nemitom
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« Reply #11 on: March 15, 2020, 03:03:34 AM »
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Very simple.... Xor all VIN byte and one constant.... for immo id ( SKZ) is same way, just other constant....
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H2Deetoo
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« Reply #12 on: March 18, 2020, 03:12:22 PM »
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Nice!
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