Pages: [1]
Author Topic: SHort KFLDRL question ME7 551K  (Read 2561 times)
black
Full Member
***

Karma: +0/-0
Offline Offline

Posts: 80


« on: March 31, 2015, 12:57:02 AM »

ldtvr_w is input for KFLDRL

so if ldtvr_w f.e. = 115% and the 115% is given to KFLDRL

how can the result of KFLDRL be only 89??

--> KFLDRL map last two lines, input ldtvr_w = 115 at given rpm:

115 -->

70 I 95 95 95 95 95 95 95 85 85 77 75 74 74 70 70 71 71
95 I 95 95 95 95 95 95 95 95 90 80 76 75 75 74 73 72 72

--> 89  Huh

did I miss something??

update -->

got it...  KFLDIMX input at given rpm was 89 (I) and (P) was 26 (I+P) = 115 so limit is 89...  Tongue
« Last Edit: March 31, 2015, 01:13:20 AM by black » Logged
Pages: [1]
  Print  
 
Jump to:  

Powered by SMF 1.1.21 | SMF © 2015, Simple Machines Page created in 0.012 seconds with 16 queries. (Pretty URLs adds 0s, 0q)