Rabbid
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« on: November 24, 2012, 12:41:04 PM »
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Hi All
I'm looking to try and work out what is used for the reference cylinder displacement when calculating load etc. Main reason is for asking is a 2.0 engine rebored or stroked out to a larger size worth writing home about.
I've searched so far but have been unsucessful.
Any pointers for dealing with changed displacement?
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Rick
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« Reply #1 on: November 24, 2012, 12:59:27 PM »
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MLMAX - do a search
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Rabbid
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« Reply #2 on: November 24, 2012, 01:21:48 PM »
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Thanks but that is maximum possible air flow for load calculation, which would be adjusted on boosted cars for example. I'm on about the actual calculation of load i.e Load = Mass ingested over Mass Standard. From what I understand mass standard is displacement in cc multiplied by 0.00122521 g[cc] http://s4wiki.com/wiki/LoadI am trying to workout where the ECU would get the displacement cc from
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Rabbid
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« Reply #3 on: November 24, 2012, 01:23:34 PM »
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So far I've found posts relating to KUMSRL and KISRM but I'm not 100% sure on how these would relate to engine load.
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Bische
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« Reply #4 on: November 25, 2012, 11:31:42 PM »
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KISRM converts rlroh_w to ps_w and KFURL converts ps_w into rl_w.
I believe you should scale KISRM to get ps_w in line with boost pressure(I dont remember the variable name off my head) and thus getting rl_w back in line. I could be wrong but that is how I would approach it.
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nyet
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« Reply #5 on: November 25, 2012, 11:52:51 PM »
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KUMSRL converts kg/hr of air into load per rpm
It is inversely proportional to displacement.
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Rabbid
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« Reply #6 on: November 28, 2012, 02:16:28 AM »
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Seems KRKTE uses displacement in its calculationt too.
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ABCD
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« Reply #7 on: November 28, 2012, 02:51:21 AM »
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KUMSIRL=Vh/2578, where Vh is cylinder volume in Litre
KRKTE = Vh*50.2624/Qstat, where Qstat is Injector static flow in gm/min.
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ABCD
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« Reply #8 on: November 28, 2012, 02:52:25 AM »
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It is inversely proportional to displacement.
Wrong KUMSIRL in directly proportional to displacement.
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« Last Edit: November 28, 2012, 11:23:41 AM by nyet »
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Rabbid
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« Reply #9 on: November 28, 2012, 07:09:04 AM »
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Certainly seeming alot more difficult than a standalone ecu which just asks for engine displacement and number of cylinders
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nyet
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« Reply #10 on: November 28, 2012, 11:33:20 AM »
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Wrong
KUMSIRL in directly proportional to displacement.
HMM. I rechecked this. As far as I can tell, KUMSRL (not KUMISRL) is, in fact, inversely proportional to displacement. I don't actually know what KUMISRL is.
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nyet
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« Reply #11 on: November 28, 2012, 11:40:56 AM »
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Here you go. You were right, KUMSRL is proportional to displacement:
(((.001072 (kg / hr)) / (1.27500 (kg / (m^3)))) / (0.5 * (1 / min))) * 100 = 2.80261438 liters
Not sure why 2.8 though, and not 2.7
Am i using the wrong density for air?
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nyet
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« Reply #12 on: November 28, 2012, 12:05:47 PM »
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Certainly seeming alot more difficult than a standalone ecu which just asks for engine displacement and number of cylinders In any case, I think ABCD definitely has it right. displacement/2578 will get you in the ballpark.
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ABCD
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« Reply #13 on: November 28, 2012, 11:55:26 PM »
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Here you go. You were right, KUMSRL is proportional to displacement:
(((.001072 (kg / hr)) / (1.27500 (kg / (m^3)))) / (0.5 * (1 / min))) * 100 = 2.80261438 liters
Not sure why 2.8 though, and not 2.7
Am i using the wrong density for air?
Hi nyet, I cud not get what have you calculated here. Pls elaborate. density of air = 1.293 gm/L at 273K
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