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Title: 5mp LDRXN Post by: turdburglar44 on December 13, 2014, 04:29:49 PM Can anyone help me out by verifying this bin has the ldrxn switch code properly implemented?
the original code has this: mov r12, #0E400h mov r13, #23Fh but it would make more sense to me if it was this: mov r12, #2400h mov r13, #23Fh the map is at 8FE400 so my logic is: 23F * 4000 = 8FC000 + 2400 = 8FE400 same with the ldrxnzk call below it ****************Removed bin. I abandoned this attempt because I realized the code I was using was not up to date. I'll eventually write my own code and get back to it. Title: Re: 5mp LDRXN Post by: masterj on December 15, 2014, 01:51:28 AM Can anyone help me out by verifying this bin has the ldrxn switch code properly implemented? the original code has this: mov r12, #0E400h mov r13, #23Fh but it would make more sense to me if it was this: mov r12, #2400h mov r13, #23Fh the map is at 8FE400 so my logic is: 23F * 4000 = 8FC000 + 2400 = 8FE400 same with the ldrxnzk call below it 23Ch × 4000h = 8F0000h I haven't looked at your file but I guess it is your "base" address. If I am correct then unless you have register with saved value 23Fh just before instruction it is 23Ch. Same as 204h for most ME7 files I've seen In this specific case I would say r13 is being used with another constant or register UPDATE: Reread your post and I think you are correct if this is not original code, then there might be error and you are right Title: Re: Post by: turdburglar44 on December 15, 2014, 09:30:22 AM Sorry for the lack of info. Posted that in a hurry. The code in question I got from the link here.
http://nefariousmotorsports.com/forum/index.php?topic=1556.0 I went through and changed the respective ram addresses and changed the call for ldrxn and ldrxnzk to look at the new sub. Anything else I need to do? |