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Title: SHort KFLDRL question ME7 551K Post by: black on March 31, 2015, 12:57:02 AM ldtvr_w is input for KFLDRL
so if ldtvr_w f.e. = 115% and the 115% is given to KFLDRL how can the result of KFLDRL be only 89?? --> KFLDRL map last two lines, input ldtvr_w = 115 at given rpm: 115 --> 70 I 95 95 95 95 95 95 95 85 85 77 75 74 74 70 70 71 71 95 I 95 95 95 95 95 95 95 95 90 80 76 75 75 74 73 72 72 --> 89 ??? did I miss something?? update --> got it... KFLDIMX input at given rpm was 89 (I) and (P) was 26 (I+P) = 115 so limit is 89... :P |