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Author Topic: What does this line of assembly code mean?  (Read 61253 times)
elRey
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« Reply #15 on: May 15, 2012, 01:49:06 PM »

Quote
the bottom 14 bits of 0x199BA is 0x199BA & 0x0x3fff = 0x19ba
the upper bits of 0x199BA is 0x18000>>14 = 6

^I don't get this at all.

Wait. Oh I see.
11001100110111010

--001100110111010 = 19ba
11000000000000000 = 18000
« Last Edit: May 15, 2012, 01:53:23 PM by elRey » Logged
elRey
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« Reply #16 on: May 15, 2012, 02:00:55 PM »

Code:
mov     r12, #0A17h
mov     r13, #206h
movbz   r14, byte_F89C
calls   82h, LookupI_825c24 ; References a lookupI table
movb    byte_381E4A, rl4
mov     r12, #848h
mov     r13, #207h
mov     r14, word_F89E
calls   82h, LookupJ_825c98 ; References a lookupJ table

mov     r12, #0A17h
mov     r13, #206h

#0A17h = 18A17 Looks right. It lands me at the map I expect.

mov     r12, #848h
mov     r13, #207h

#848h = 18848 Looks wrong. It lands me in the middle of a map (wrong map).

??
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matchew
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« Reply #17 on: May 15, 2012, 02:49:48 PM »

mov     r12, #848h
mov     r13, #207h

#848h = 18848 Looks wrong. It lands me in the middle of a map (wrong map).

??

Try 0x1C848....

The difference is 206 vs 207
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elRey
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« Reply #18 on: May 15, 2012, 03:03:42 PM »

right on the dot. Thanks. I can't say I understand it, but I believe I'm seeing the pattern.

Thanks guys.
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nyet
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« Reply #19 on: May 15, 2012, 04:05:13 PM »

Try 0x1C848....

The difference is 206 vs 207

I'm curious as to why... is r13 used to modify dpp in the subroutine?
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ArgDub
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« Reply #20 on: May 15, 2012, 04:28:22 PM »

I'm curious as to why... is r13 used to modify dpp in the subroutine?

What Andy's plugin names as LookupJ is a 1d map lookup function that returns a 16bit unsigned value, X axis is also 16bit unsigned. The parameters passed are: r12 = map address, r13 = Map DPP, r14: X variable.
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nyet
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« Reply #21 on: May 15, 2012, 04:33:33 PM »

right on the dot. Thanks. I can't say I understand it, but I believe I'm seeing the pattern.

If R13 is used to pass DPP

0x207<<14 | 0x848 = 0x81c848

I'm assuming the rom is mapped to 0x80000, which means the offset into the ROM is 0x1c848

or, to make things easier

0x7<<14 | 0x848 = 0x1c848
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ArgDub
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« Reply #22 on: May 15, 2012, 04:46:12 PM »

Correct, function LookupJ expects a pointer (r13 << 14 | r12) to map's X_AxisLength, following X_AxisLength is the X_Axis itself and the map is next to the axis
« Last Edit: May 15, 2012, 07:19:28 PM by ArgDub » Logged
elRey
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« Reply #23 on: October 20, 2012, 04:39:29 PM »

Code:
mov     r12, #2B94h     ; KFZW2 Map
mov     r13, #3BC4h     ; KFZW2 Load axis
mov     r14, word_380CDE
mov     r15, word_380CEE
calls   0, sub_2B24     ; KFZW2 Lookup

How does the sub_2B24 WLookup2D_Spark function know where the RPM axis is? (which is @ 13B64)

code right before lookup:

Code:
ZWGRU:
mov     [-r0], r9
mov     [-r0], r7
mov     [-r0], r6
sub     r0, #2
mov     r4, word_382C14
extp    #20Ah, #1
cmp     r4, word_829FE4
jmpr    cc_NC, loc_8B8E4C

Thanks,
Rey
« Last Edit: October 20, 2012, 04:50:36 PM by elRey » Logged
rajivc666
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« Reply #24 on: October 21, 2012, 06:39:18 AM »

The memory locations 380cde and 380cee contains a factor for load and rpm, since the dimensions of the tables are known, starting point and factors of the axes are sufficient to look up the table. 
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elRey
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« Reply #25 on: October 21, 2012, 11:03:14 AM »

Map and axis are in different locations. i.e. the axis are not next to map. Nor are they next to each other. The code only references the map location and one of the axis location. How does it know where the other axis is located?

380cde and 380cee I assumed were the inputs for the lookup. Am I wrong?
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matchew
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« Reply #26 on: October 21, 2012, 11:35:51 AM »

0x380CDE and 0x380CEE I assumed were the inputs for the lookup. Am I wrong?

No you are correct. These are the variables that each axis uses. One of which is tied to a specific axis, the other can be applied to various different axis.
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rajivc666
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« Reply #27 on: October 21, 2012, 11:42:04 AM »

One thing you should understand is that these axes in definitions are made for humans, the ecu may not be using it as projected in definitions. If you decode the part were the memory locations 0x380CDE and 0x380CEE get their values you will understand.
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phila_dot
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« Reply #28 on: October 21, 2012, 01:18:16 PM »

If you decode the part were the memory locations 0x380CDE and 0x380CEE get their values you will understand.

This.

The axis is referenced in the assignment of the Stutzstellen variables.

mov     r12, #0C1h ; '-' ; Move Word                  
movbz   r13, nmot       ; Move Byte Zero Extend        
mov     r14, SNM16ZUUB_w ; Move Word                  
calls   0, sub_75D2   ; Call Inter-Segment Subroutine
mov     SNM16ZUUB_w, r4 ; Move Word                    
« Last Edit: November 23, 2012, 11:31:54 AM by phila_dot » Logged
elRey
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« Reply #29 on: November 23, 2012, 10:13:19 AM »

Ah I get it. That last line keeps the axis location in memory. Cool.
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