ddillenger
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« on: February 20, 2013, 04:19:16 PM »
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I'm stuck. I genuinely have searched and searched, I know where I think it should be, but unless the conversion is different than what I'm used to the value makes no sense.
1cde2 would be where I'd expect to find it, but I could be completely off base here. My disassembly skills aren't quite up to the task, so here I am, asking for assistance.
Thanks guys.
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Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your experience!
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prj
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« Reply #1 on: February 20, 2013, 05:33:41 PM »
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Try 0x189FA, ASM pattern matched there, didn't bother manually verifying.
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ddillenger
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« Reply #2 on: February 20, 2013, 06:02:02 PM »
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Using that location nets a result of 7.33, I don't believe that is correct-lol.
Thanks for the interest.
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Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your experience!
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prj
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« Reply #3 on: February 20, 2013, 06:13:38 PM »
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I agree, that just means the pattern matched in the wrong place... I don't have time to disassemble it right now, sorry.
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phila_dot
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« Reply #4 on: February 20, 2013, 07:13:39 PM »
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Quick look, it appears to be 8 bit at 0x818F9A.
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ddillenger
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« Reply #5 on: February 20, 2013, 07:55:15 PM »
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0x818F9A or 0x18f9a?
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Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your experience!
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phila_dot
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« Reply #6 on: February 20, 2013, 08:19:04 PM »
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In real life 0x818F9A, in WinOLS 0x18F9A.
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ddillenger
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« Reply #7 on: February 20, 2013, 08:51:56 PM »
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Sigh, I don't understand what's going on here. That address has a value of .0095 in 8bit.
This is what I was talking about. I was sure I had it several times, then went to look at the data only to get a nonsense value. Is the equation different? .000111*x?
I appreciate the assistance guys. Not quite sure what's going on here.
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Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your experience!
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nyet
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« Reply #8 on: February 20, 2013, 08:54:09 PM »
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Absolutely. 8-bit values will almost always have a different scalar than their "equivalent" 16-bit values
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