DrGeorgeTompson
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« Reply #30 on: March 13, 2014, 10:20:35 AM »
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BTW that one is VERY extreme because that is a tight wastegate system. You will not need as much of a dip for k03s  A very slight dip is probably more than sufficient. Noted. I dont really have a dip at this moment, is more of a taper. So i'll see what i can get it to do and post logs later. |
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dream3R
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« Reply #31 on: March 16, 2014, 02:04:57 AM »
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DrGeorgeTompson
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« Reply #32 on: March 20, 2014, 12:01:11 PM »
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Sorry for going dark for a while. I've been making some progress though not much. Funktionsrahmen page 873:
Control algorithms are defined thus:
Proportional component ldptv = (LDRQ0DY (or LDRQ0S) - KFLDRQ2 (or 0)) x lde
Integral component lditv = lditv(i-1) + KFLDRQ1 (or LDRQ1ST) x lde(i-1)
Derivative component ldrdtv = (lde - lde(i-1)) x KFLDRQ2 (or 0)
where lde is the charge pressure control error, i.e. (set point - process value) or (DV - MV)
what is "i" in these algorithms? |
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nyet
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« Reply #33 on: March 20, 2014, 12:40:50 PM »
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"i" is "this sample" so lde(i-1) is "the last sample of lde" numerical integration and differentiation... might want to brush up on your math, since you are delving into the PID. out of curiosity, what kind of Dr. are you? |
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ME7.1 tuning guideECUx PlotME7Sum checksumTrim heatmap toolPlease do not ask me for tunes. I'm here to help people make their own. Do not PM me technical questions! Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your ex
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DrGeorgeTompson
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« Reply #34 on: March 20, 2014, 02:35:20 PM »
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"i" is "this sample"
so lde(i-1) is "the last sample of lde"
numerical integration and differentiation... might want to brush up on your math, since you are delving into the PID.
Thanks. I have a pretty fair understanding of PIDs and while i'm familiar with calculus, I'm going to take a 90's kid approach to this (at first) and just poke things until it works better. I'll keep looking at my logs and adjusting accordingly out of curiosity, what kind of Dr. are you? It is merely my online alias. My name is actually Alan  |
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nyet
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« Reply #35 on: March 20, 2014, 03:10:43 PM »
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Numerically integrating means simply summing samples over a period of time, i.e.
I(i-1) = f(i-n) + .... + f(i-2) + f(i-1)
so I(i) = I(i-1) + f(i) is the easiest way to get a running I(i)
Differentiation is dx/dt. Numerical differentiation is simply (f(i)-f(i-1))/(i-(i-1)), or f(i)-f(i-1)
In this case, f(i) is lde(i).
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« Last Edit: March 20, 2014, 03:13:26 PM by nyet »
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ME7.1 tuning guideECUx PlotME7Sum checksumTrim heatmap toolPlease do not ask me for tunes. I'm here to help people make their own. Do not PM me technical questions! Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your ex
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userpike
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« Reply #36 on: March 20, 2014, 11:04:13 PM »
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It is merely my online alias. My name is actually Alan You aren't the verbal judo guy??? |
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DrGeorgeTompson
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« Reply #37 on: March 20, 2014, 11:19:51 PM »
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You aren't the verbal judo guy???
Unfortunately no :C I have failed the nefmoto community. |
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DrGeorgeTompson
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« Reply #38 on: March 24, 2014, 01:21:03 PM »
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How does KFLDRQ0 apply? Or does it? i cant seem to find anything about it.
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nyet
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« Reply #39 on: March 24, 2014, 01:30:58 PM »
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How does KFLDRQ0 apply? Or does it? i cant seem to find anything about it.
? Q0 is the proportional component. From your OWN post: Proportional component ldptv = (LDRQ0DY (or LDRQ0S) - KFLDRQ2 (or 0)) x lde
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ME7.1 tuning guideECUx PlotME7Sum checksumTrim heatmap toolPlease do not ask me for tunes. I'm here to help people make their own. Do not PM me technical questions! Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your ex
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DrGeorgeTompson
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« Reply #40 on: March 24, 2014, 01:33:45 PM »
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?
Q0 is the proportional component.
Right, But that uses LDRQ0S. Does it use KFLDRQ0 when the system is not static? |
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nyet
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« Reply #41 on: March 24, 2014, 01:35:03 PM »
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Right, But that uses LDRQ0S. Does it use KFLDRQ0 when the system is not static?
Depends on the version; there are many variants of PIDs. If the FR does not mention it, you'll have to disassemble the specific image you are looking at to figure out how it is used. |
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ME7.1 tuning guideECUx PlotME7Sum checksumTrim heatmap toolPlease do not ask me for tunes. I'm here to help people make their own. Do not PM me technical questions! Please, ask all questions on the forums! Doing so will ensure the next person with the same issue gets the opportunity to learn from your ex
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DrGeorgeTompson
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« Reply #42 on: March 24, 2014, 01:37:44 PM »
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Depends on the version; there are many variants of PIDs. If the FR does not mention it, you'll have to disassemble the specific image you are looking at to figure out how it is used.
guuuhhh. Well, the wastegate is acting better now. I'm making progress. |
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Lost
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« Reply #43 on: March 25, 2014, 01:28:16 PM »
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guuuhhh. Well, the wastegate is acting better now. I'm making progress.
You gotta lower that KFLDIMX, way more |
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DrGeorgeTompson
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« Reply #44 on: March 25, 2014, 01:44:52 PM »
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You gotta lower that KFLDIMX, way more I'm glad you said that cause that's what I'm currently tuning Is there a particular fashion in which i should tune it? Where should i start? I've started on the last column. Is that proper? |
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« Last Edit: March 25, 2014, 01:47:12 PM by DrGeorgeTompson »
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